A titration curve is generated by titrating of CH₃COOH with KOH at

CHEMISTRY · Multi-part · A Level · Chemistry · Acids and bases · Acids and bases

Problem

A titration curve is generated by titrating

25.00\,\text{mL}

0.100\,\text{M}

CH₃COOH with

0.120\,\text{M}

KOH at

25\,^\circ\text{C}

. Only points in the post-equivalence region are of interest in this experiment. Three specific additions of KOH beyond the equivalence point are highlighted:

2.00\,\text{mL}

10.00\,\text{mL}

, and

25.00\,\text{mL}

of additional titrant. Assume ideal behavior and that volumes are additive. Ignore any contribution of the acetate ion to the pH in the strongly basic post-equivalence region. (1) Part 1: Calculate the volume of KOH (in mL) required to reach the equivalence point. (2) Part 2: For each of the three post-equivalence additions (

2.00\,\text{mL}

10.00\,\text{mL}

, and

25.00\,\text{mL}

), calculate the pH of the solution in the flask. (3) Part 3: Using your results from part (b), determine the approximate slope

\Delta\text{pH}/\Delta V

between (i)

2.00\,\text{mL}

and

10.00\,\text{mL}

and (ii)

10.00\,\text{mL}

and

25.00\,\text{mL}

of excess titrant. (4) Part 4: Explain how the slopes calculated in part (c) illustrate the shape of the titration curve in the post-equivalence region.

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