For the reaction S2O82−(aq)+2I−(aq)→2SO42−(aq)+I2(aq), the rate law is first order in S2O82− and first order in I−. In Trial 1, [S2O82−]=0.10M and [I−]=0.10M, giving an initial rate of 2.0×10−5Ms−1. In Trial 2, only [S2O82−] is doubled to 0.20M. Determine the initial rate in Trial 2 and briefly explain how the change in concentration affects collision frequency.