If , then…

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

If yln⁡y=xy\ln y = x, then dydx\dfrac{dy}{dx} equals (a) 1y(ln⁡y+1)\displaystyle\frac{1}{y(\ln y + 1)} (b) 1yln⁡y+1\displaystyle\frac{1}{y\ln y + 1} (c) 1ln⁡y+1\displaystyle\frac{1}{\ln y + 1} (d) 1ln⁡y\displaystyle\frac{1}{\ln y}

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