A particle is projected from a tower of height with velocity at

PHYSICS · Subjective · CBSE · Physics · Motion in a Plane · Motion in a Plane

Problem

A particle is projected from a tower of height 25 m25\,\mathrm{m} with velocity 202 m/s20\sqrt2\,\mathrm{m/s} at 45∘45^\circ. Find the time when the particle strikes the ground, the horizontal distance from the foot of the tower where it strikes, and its distance from the point of projection at collision. Take g=10 m/s2g=10\,\mathrm{m/s^2}.

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