The normal at the point on a circle cuts the circle at the point

MATHEMATICS · Single correct · A Level · Mathematics · Coordinate geometry in the (x y) plane · Coordinate geometry in the (x y) plane

Problem

The normal at the point (3,4)(3, 4) on a circle cuts the circle at the point (−1,−2)(-1, -2) . Then, the equation of the circle is (1) x2+y2+2x−2y−13=0x^2 + y^2 + 2x - 2y - 13 = 0 (2) x2+y2−2x−2y−11=0x^2 + y^2 - 2x - 2y - 11 = 0 (3) x2+y2−2x+2y+12=0x^2 + y^2 - 2x + 2y + 12 = 0 (4) x2+y2−2x−2y+14=0x^2 + y^2 - 2x - 2y + 14 = 0

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