In an ideal step-up transformer the primary voltage is and the turns ratio is

PHYSICS · Single correct · CBSE · Physics · Alternating Current · Alternating Current

Problem

In an ideal step-up transformer the primary voltage is vp=170sin⁡(100πt) Vv_p = 170\sin(100\pi t)\,\text{V} and the turns ratio is Ns:Np=10:1N_s:N_p = 10:1. Determine the earliest positive time (in milliseconds, correct to two significant figures) at which the instantaneous secondary voltage first attains +800 V+800\,\text{V}. (a) 5.0 ms5.0\,\text{ms} (b) 1.1 ms1.1\,\text{ms} (c) 1.6 ms1.6\,\text{ms} (d) 0.79 ms0.79\,\text{ms}

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