During the derivation of centripetal acceleration

PHYSICS · Single correct · CBSE · Physics · Motion in a Plane · Motion in a Plane

Problem

During the derivation of centripetal acceleration, the change in velocity vector Δv\Delta\mathbf v and the change in position vector Δr\Delta\mathbf r over a very small time interval satisfy a relation based on the similarity of triangles. Which relation is used? (a) ∣Δv∣v=2 ∣Δr∣r\dfrac{|\Delta\mathbf v|}{v}=2\,\dfrac{|\Delta\mathbf r|}{r} (b) ∣Δv∣v=∣Δr∣2r\dfrac{|\Delta\mathbf v|}{v}=\dfrac{|\Delta\mathbf r|}{2r} (c) ∣Δv∣v=∣Δr∣r\dfrac{|\Delta\mathbf v|}{v}=\dfrac{|\Delta\mathbf r|}{r} (d) ∣Δv∣v=(∣Δr∣r)2\dfrac{|\Delta\mathbf v|}{v}=\left(\dfrac{|\Delta\mathbf r|}{r}\right)^2

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