A solid cylinder of mass rolls without slipping at speed on a horizontal surface

PHYSICS · Single correct · CBSE · Physics · System of Particles and Rotational Motion · System of Particles and Rotational Motion

Problem

A solid cylinder of mass MM rolls without slipping at speed vv on a horizontal surface. Student A models the cylinder as a single particle and calculates its kinetic energy as KA=12Mv2K_A=\frac12 M v^{2}. Student B treats the cylinder as a rigid system and includes both translation and rotation, obtaining KB=12Mv2+12Iω2K_B=\frac12 M v^{2}+\frac12 I\omega^{2} with I=12MR2I=\frac12 M R^{2}. By what factor does Student A’s value differ from Student B’s correct value? (a) 12\dfrac12 (b) 43\dfrac43 (c) 23\dfrac23 (d) 11

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