A chemist is designing two versions of a synthetic polymer

CHEMISTRY · Single correct · A Level · Chemistry · Bonding · Bonding

Problem

A chemist is designing two versions of a synthetic polymer. Version A has –CH₃ side groups, whereas Version B substitutes each –CH₃ with –Cl. Which statement most accurately predicts how this substitution affects intermolecular forces between polymer chains? (a) Version B experiences weaker London dispersion forces because the electronegativity of chlorine withdraws electron density, decreasing polarizability (b) Version B experiences stronger London dispersion forces because the –Cl groups increase polarizability (c) Version B experiences stronger hydrogen bonding because the highly electronegative chlorine can accept hydrogen bonds from neighboring chains (d) Version A experiences stronger dipole–dipole forces because C ⁣− ⁣H\mathrm{C\!-\!H} bonds are polar, whereas C ⁣− ⁣Cl\mathrm{C\!-\!Cl} bonds are nonpolar overall

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