A timing system records elapsed time (in s) as a strictly increasing

MATHEMATICS · Multi-part · AP · Calculus AB · Differentiation: Composite, Implicit, and Inverse Functions · Differentiation: Composite, Implicit, and Inverse Functions

Problem

A timing system records elapsed time τ\tau (in s) as a strictly increasing, twice-differentiable function of displacement ss (in m) along a track: τ=f(s)\tau=f(s). Consequently, displacement can be expressed as the inverse function s=f−1(τ)s=f^{-1}(\tau). (a) Derive a formula for the velocity dsdτ\displaystyle \frac{ds}{d\tau} in terms of f′(s)f'(s) evaluated at the appropriate displacement. (b) Show that the acceleration d2sdτ2\displaystyle \frac{d^{2}s}{d\tau^{2}} can be written in the form −f′′(s)[f′(s)]3-\dfrac{f''(s)}{[f'(s)]^{3}}, specifying clearly at which displacement value the derivatives of ff are to be evaluated. (c) For s=10 ms=10\text{ m} the measurements are f′(10)=4 s/mf'(10)=4\text{ s/m} and f′′(10)=0.30 s/m2f''(10)=0.30\text{ s/m}^{2}. Compute the instantaneous velocity and acceleration when the particle is at s=10 ms=10\text{ m}. (d) Interpret the sign of the acceleration you found in part (c) in the context of the particle’s motion along the track.

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