Solid calcium carbonate decomposes at high temperature according to At 1010 K

CHEMISTRY · Multi-part · A Level · Chemistry · Chemical equilibria (Le Chatelier’s principle and Kc) · Chemical equilibria (Le Chatelier’s principle and Kc)

Problem

Solid calcium carbonate decomposes at high temperature according to CaCO3(s)⇌CaO(s)+CO2(g)\text{CaCO}_3(s) \rightleftharpoons \text{CaO}(s) + \text{CO}_2(g) At 1010 K, the equilibrium constant for the reaction is Kp=0.25 atmK_p = 0.25\,\text{atm}. A rigid 10.0 L container at 1010 K is filled with 0.200 mol of CO2(g)\text{CO}_2(g) along with excess solid CaCO3\text{CaCO}_3 and CaO\text{CaO} already present so that the heterogeneous equilibrium can establish. (a) Write the equilibrium–constant expression appropriate for this reaction at 1010 K. (b) Determine the equilibrium partial pressure of CO2(g)\text{CO}_2(g) in the container after equilibrium is reached. Clearly indicate how you use the given information to arrive at your answer. (c) Calculate the mass of CaCO3\text{CaCO}_3 (in grams) that decomposes, if any, during the attainment of equilibrium. The molar mass of CaCO3\text{CaCO}_3 is 100.1 g mol−1100.1\,\text{g mol}^{-1}. State whether decomposition occurs and justify your conclusion quantitatively.

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