Consider the differential equation with equilibrium solutions at and

MATHEMATICS · Single correct · AP · Calculus AB · Differential Equations · Differential Equations

Problem

Consider the differential equation dydx=y(1−y)\dfrac{dy}{dx}=y(1-y) with equilibrium solutions at y=0y=0 and y=1y=1. Which statement most accurately describes the behavior of the solution curve that passes through the point (0,2)(0,2) as xx increases? (a) The curve decreases and crosses y=1y=1 since the slope there is negative, continuing downward afterward. (b) The curve decreases and approaches y=0y=0, leveling off without crossing that line. (c) The curve decreases and approaches y=1y=1, leveling off without crossing that line. (d) The curve increases without bound because dydx\dfrac{dy}{dx} is always positive when y>0y>0."

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