, where is a constant. Then…

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

f(x)=∣x3x23x21−64pp2p3∣f(x)=\begin{vmatrix}x^3 & x^2 & 3x^2 \\ 1 & -6 & 4 \\ p & p^2 & p^3\end{vmatrix}, where pp is a constant. Then d3f(x)dx3\frac{d^3f(x)}{dx^3} is (a) Proportional to x2x^2 (b) Proportional to xx (c) Proportional to x3x^3 (d) A constant

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