Let A= ( 2^ 5 16^ 3 2 8^ -2 ) (4^ 3 32^ -1 ).

MATHEMATICS · Multi-part · GCSE · Mathematics · Number · Number

Problem

Let

A=\left(\frac{2^{5}\times16^{\frac{3}{2}}}{8^{-2}}\right)\div\bigl(4^{3}\times32^{-1}\bigr).

(i) Express every numerical factor in

A

as a power of

2

. (ii) Simplify step by step to write

A

in the form

2^{k}

and determine the value of

k

. (iii) Hence find the numerical value of

A