A thin rod of length is hinged at

PHYSICS · Single correct · CBSE · Physics · System of Particles and Rotational Motion · System of Particles and Rotational Motion

Problem

A thin rod ABAB of length 0.50 m0.50\,\text m is hinged at AA. A force of 20 N20\,\text N acts at BB, making an angle 30∘30^{\circ} with the rod and tending to rotate it anticlockwise. At the same time, a force of 15 N15\,\text N acts perpendicular to the rod at a point 0.25 m0.25\,\text m from AA and tends to rotate it clockwise. Taking anticlockwise torque as positive, the net torque about the hinge is (a) +6.25 N m+6.25\,\text{N m} (b) +4.91 N m+4.91\,\text{N m} (c) −2.50 N m-2.50\,\text{N m} (d) +1.25 N m+1.25\,\text{N m}

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