Let be the portion of the graph of from to with .

MATHEMATICS · Multi-part · AP · Calculus BC · Applications of Integration · Applications of Integration

Problem

Let CC be the portion of the graph of y=cosh⁡xy=\cosh x from x=0x=0 to x=ax=a with a>0a>0. (a) Compute dydx\dfrac{dy}{dx} for y=cosh⁡xy=\cosh x. Show all steps. (b) Verify algebraically that 1+(dydx)2=cosh⁡x\sqrt{1+\left(\dfrac{dy}{dx}\right)^2}=\cosh x for every real xx. Show each identity you use. (c) Explain, without carrying out the integration, why the result in part (b) implies that the arc length of CC can be obtained by evaluating ∫0acosh⁡x dx\displaystyle \int_0^{a} \cosh x\,dx. Your explanation should refer explicitly to the definition of arc length for a function y=f(x)y=f(x).

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