The balanced equation for the reaction of sulfite ion with permanganate ion in acidic…

CHEMISTRY · Single correct · A Level · Chemistry · Oxidation, reduction and redox reactions · Oxidation, reduction and redox reactions

Problem

The balanced equation for the reaction of sulfite ion with permanganate ion in acidic solution is 5 SO32−+2 MnO4−+6 H+→5 SO42−+2 Mn2++3 H2O5\,\text{SO}_3^{2-}+2\,\text{MnO}_4^-+6\,\text{H}^+\rightarrow5\,\text{SO}_4^{2-}+2\,\text{Mn}^{2+}+3\,\text{H}_2\text{O} Which of the following best explains why the coefficient in front of SO32−\text{SO}_3^{2-} is 5? (a) Charge balance can only be obtained on both sides of the equation when the coefficient of SO32−\text{SO}_3^{2-} is five. (b) Five SO32−\text{SO}_3^{2-} ions each lose two electrons, supplying the ten electrons needed to reduce two MnO4− ions\text{MnO}_4^-\,\text{ions} to Mn2+\text{Mn}^{2+}. (c) Each SO32−\text{SO}_3^{2-} ion loses one electron; five ions therefore provide enough electrons to match those gained by the permanganate ions. (d) Because sulfur is in the +4+4 oxidation state in SO32−\text{SO}_3^{2-}, five such ions are needed so the total number of sulfur atoms is conserved.

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