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The freezing point of 0.08 molal is
CHEMISTRY · Subjective · CBSE · Chemistry · Solutions · Solutions
Problem
The freezing point of 0.08 molal
NaHSO
4
\text{NaHSO}_4
NaHSO
4
is
−
0.345
∘
C
-0.345^\circ\text{C}
−
0.34
5
∘
C
. Calculate the percentage of
HSO
4
−
\text{HSO}_4^-
HSO
4
−
ions that transfers a proton to water. Assume 100% ionisation of
NaHSO
4
\text{NaHSO}_4
NaHSO
4
and
K
f
K_f
K
f
for
H
2
O
=
1.86
K molality
−
1
\text{H}_2\text{O} = 1.86 \text{ K molality}^{-1}
H
2
O
=
1.86
K molality
−
1
.
Related theory
Colligative Properties
Solutions
Abnormal Molar Mass
Abnormal molecular mass
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