Let the sum of the maximum and the minimum values of the function be

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Problem

Let the sum of the maximum and the minimum values of the function f(x)=2x2−3x+82x2+3x+8f(x) = \frac{2x^2 - 3x + 8}{2x^2 + 3x + 8} be mn\frac{m}{n}, where gcd(m,n)=1\text{gcd}(m, n) = 1 . Then m+nm + n is equal to: (A) 182 (B) 217 (C) 195 (D) 201

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