The function is defined by f(x)= cases x+2, & x1

MATHEMATICS · Single correct · AP · Calculus AB · Limits and Continuity · Limits and Continuity

Problem

The function ff is defined by f(x)={x+2,x<1,4,x=1,5−x,x>1.f(x)=\begin{cases} x+2, & x<1,\\ 4, & x=1,\\ 5-x, & x>1. \end{cases} Which of the following correctly describes the behavior of ff at x=1x=1? (a) lim⁡x→1f(x)=4\displaystyle \lim_{x\to 1} f(x)=4 because f(1)=4f(1)=4. (b) lim⁡x→1f(x)\displaystyle \lim_{x\to 1} f(x) does not exist because ff is undefined at x=1x=1. (c) lim⁡x→1−f(x)=3 and lim⁡x→1+f(x)=4\displaystyle \lim_{x\to 1^{-}} f(x)=3\text{ and }\lim_{x\to 1^{+}} f(x)=4. (d) lim⁡x→1−f(x)=4 and lim⁡x→1+f(x)=3\displaystyle \lim_{x\to 1^{-}} f(x)=4\text{ and }\lim_{x\to 1^{+}} f(x)=3.

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