The potential energy of a particle varies with distance from a fixed origin as where…

PHYSICS · Single correct · CBSE · Physics · Units and Measurements · Units and Measurements

Problem

The potential energy

U

of a particle varies with distance

x

from a fixed origin as

U = \frac{A\sqrt{x}}{x^2 + B}

where

A

and

B

are dimensional constants. The dimensional formula for

AB

is (A)

[M^1 L^{\frac{7}{2}} T^{-2}]

(B)

[M^1 L^{\frac{11}{2}} T^{-2}]

(C)

[M^1 L^{\frac{5}{2}} T^{-2}]

(D)

[M^1 L^{\frac{9}{2}} T^{-2}]