Clockwise mesh currents and are assigned to two adjacent loops that share a resistor

PHYSICS · Single correct · AP · Physics 2: Algebra-based · Electric Circuits · Electric Circuits

Problem

Clockwise mesh currents

I_1

and

I_2

are assigned to two adjacent loops that share a resistor

R

. Taking the positive direction through

R

to be the same as that of

I_1

, the current through

R

is (a)

I_1+I_2

(b)

I_2-I_1

(c)

I_1-I_2

(d)

\dfrac{I_1I_2}{I_1+I_2}