The function is continuous on

MATHEMATICS · Multi-part · AP · Calculus AB · Limits and Continuity · Limits and Continuity

Problem

The function h(x)=x5−3x−1h(x)=x^{5}-3x-1 is continuous on [1,2][1,2]. A numerical approximation of a zero of hh will be obtained by repeatedly halving an initial interval that brackets the zero. (a) Show that h(1)h(1) and h(2)h(2) have opposite signs and hence that hh has at least one zero in (1,2)(1,2). (b) After nn successive halvings of the interval [1,2][1,2], the length of the bracketing interval is 12n\dfrac{1}{2^{n}}. Determine the least integer nn such that this length is less than 10−410^{-4}. Show your reasoning clearly. (c) State the maximum possible absolute error of any approximation produced after the number of halvings found in part (b).

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