In an experiment to determine the acceleration due to gravity

PHYSICS · Single correct · A Level · Physics · Measurements and their errors · Measurements and their errors

Problem

In an experiment to determine the acceleration due to gravity gg, the formula used for the time period of a periodic motion is T=2π7(R−r)5gT = 2\pi\sqrt{\frac{7(R-r)}{5g}} . The values of RR and rr are measured to be (60±1)(60 \pm 1) mm and (10±1)(10 \pm 1) mm, respectively. In five successive measurements, the time period is found to be 0.52 s, 0.56 s, 0.57 s, 0.54 s and 0.59 s. The least count of the watch used for the measurement of time period is 0.01 s. Which of the following statement(s) is (are) true? [Adv. 2016] (1) The error in the measurement of rr is 10% (2) The error in the measurement of TT is 3.75% (3) The error in the measurement of TT is 2% (4) The error in the determined value of gg is 11%

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