A region R in the first quadrant is bounded on the left by

MATHEMATICS · Multi-part · AP · Calculus AB · Applications of Integration · Applications of Integration

Problem

A region R in the first quadrant is bounded on the left by x=1x = 1, on the right by x=3x = 3, above by y=6xy = \dfrac{6}{x}, and below by y=0y = 0. A parameter aa (with a>0a > 0) is introduced by translating the line of revolution: the region is revolved about the vertical line x=−ax = -a. (1) Part 1: (a) For general a>0a > 0, write an expression for the volume V(a)V(a) of the resulting solid as a single definite integral in whichever variable of integration gives an integrand that is independent of aa. Clearly indicate your limits of integration and provide justification for your orientation choice. (2) Part 2: (b) Evaluate the integral from part (a) to obtain a simplified formula for V(a)V(a). (3) Part 3: (c) Show that your result from part (b) can be written in the form V(a)=kπ(a+c)2V(a) = k\pi(a + c)^2, where kk and cc are constants to be determined. State the values of kk and cc. (4) Part 4: (d) Interpret how the translation distance aa affects the volume of the solid, referring explicitly to your formula from part (c).

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