The energy and capacity of a charged parallel plate capacitor are and respectively

PHYSICS · Single correct · CBSE · Physics · Electrostatic Potential and Capacitance · Electrostatic Potential and Capacitance

Problem

The energy and capacity of a charged parallel plate capacitor are

E

and

C

respectively. Now a dielectric slab of

\epsilon_r = 6

is inserted in it then energy and capacity becomes (Assuming charge on plates remains constant): (1999) (a)

6E, 6C

(b)

E, C

(c)

\frac{E}{6}, 6C

(d)

E, 6C