A uniform metre stick is pivoted at the mark

PHYSICS · Single correct · CBSE · Physics · System of Particles and Rotational Motion · System of Particles and Rotational Motion

Problem

A uniform metre stick is pivoted at the

20\,\text{cm}

mark. Two vertical downward forces act:

F_1=5\,\text N

at the

0\,\text{cm}

mark and

F_2=8\,\text N

at the

55\,\text{cm}

mark. Taking counter-clockwise torque about the pivot as positive, which of the following gives the magnitude and sign of the net torque? (a)

+1.8\,\text{N m}

(counter-clockwise) (b)

-1.0\,\text{N m}

(clockwise) (c)

-1.8\,\text{N m}

(clockwise) (d)

-3.8\,\text{N m}

(clockwise)