The displacement of a particle is m

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

The displacement of a particle is s(t)=k(1+bt)2s(t)=\dfrac{k}{(1+bt)^{2}} m, where kk and bb are positive constants. Which expression gives the velocity v(t)v(t)? (a) v(t)=+2kb(1+bt)−3v(t)=+2kb(1+bt)^{-3} (b) v(t)=−2k(1+bt)−3v(t)=-2k(1+bt)^{-3} (c) v(t)=−2kb(1+bt)−3v(t)=-2kb(1+bt)^{-3} (d) v(t)=−2kb(1+bt)−2v(t)=-2kb(1+bt)^{-2}

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