Reaction quotient is

CHEMISTRY · Single correct · A Level · Chemistry · Electrode potentials · Electrode potentials

Problem

\text{Zn} + \text{Cu}^{2+}(\text{aq}) \rightleftharpoons \text{Cu} + \text{Zn}^{2+}(\text{aq})

Q = \frac{[\text{Zn}^{2+}]}{[\text{Cu}^{2+}]}

E^\circ_{\text{cell}} = 1.10\,\text{V}

E_{\text{cell}}

will be

1.1591\,\text{V}

when: (a)

[\text{Cu}^{2+}]/[\text{Zn}^{2+}] = 0.01

(b)

[\text{Zn}^{2+}]/[\text{Cu}^{2+}] = 0.01

(c)

[\text{Zn}^{2+}]/[\text{Cu}^{2+}] = 0.1

(d)

[\text{Zn}^{2+}]/[\text{Cu}^{2+}] = 1