Let , then is equal to…

MATHEMATICS · Single correct · AP · Calculus BC · Infinite Sequences and Series · Infinite Sequences and Series

Problem

Let α=lim⁡n→∞(13−12)+(23−22)+⋯+(n3−n2)n4\alpha = \lim_{n \rightarrow \infty} \frac{(1^3 - 1^2) + (2^3 - 2^2) + \dots + (n^3 - n^2)}{n^4} , then α\alpha is equal to : (a) 13\frac{1}{3} (b) 14\frac{1}{4} (c) 12\frac{1}{2} (d) non-existent

Related theory

Browse the problem library