A seconds pendulum is a simple pendulum whose period is exactly at sea level where .

PHYSICS · Multi-part · A Level · Physics · Fields and their consequences · Fields and their consequences

Problem

A seconds pendulum is a simple pendulum whose period is exactly 2 s2\,\text{s} at sea level where g=9.80 m s−2g = 9.80\,\text{m s}^{-2}. (i) Express the period TT of this pendulum when it is taken to a depth dd inside Earth in terms of the local value of gg at that depth. (ii) Using an appropriate approximation for small dd, determine the depth at which the period becomes 0.5%0.5\% longer than 2 s2\,\text{s}. (iii) Comment on whether the same 0.5%0.5\% change in period would occur at a height equal in magnitude to the depth calculated. Support your answer with quantitative reasoning.

Related theory

Browse the problem library