PHYSICS · Single correct · AP · Physics 2: Algebra-based · Electric Circuits · Electric Circuits
Problem
Two currents enter a node: I1(t)=4sin(ωt)A and I2(t)=2A. One current leaves the node: I3(t)=3cos(ωt)A. Which expression gives the current I4(t) in the remaining branch that also leaves the node?
(a) I4(t)=4sin(ωt)+2+3cos(ωt)A
(b) I4(t)=4sin(ωt)+2−3cos(ωt)A
(c) I4(t)=−4sin(ωt)−2+3cos(ωt)A
(d) I4(t)=4sin(ωt)−2−3cos(ωt)A