At a particle moving in a straight line has velocity

PHYSICS · Single correct · CBSE · Physics · Motion in a Straight Line · Motion in a Straight Line

Problem

At t=5 st=5\text{ s} a particle moving in a straight line has velocity v(5)=−3 ft/sv(5)=-3\text{ ft/s}. One second later its velocity is v(6)=−7 ft/sv(6)=-7\text{ ft/s}. Which statement best describes the particle’s acceleration at t=5 st=5\text{ s}? (a) The acceleration is positive because the particle’s speed is increasing. (b) The sign of the acceleration cannot be determined with only two velocity values. (c) The acceleration is negative because the velocity is becoming more negative over time. (d) The acceleration is positive because v(6)−v(5)6−5=4 ft/s2\dfrac{v(6)-v(5)}{6-5}=4\,\text{ft/s}^2.

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