The Bohr radius for the ground state of hydrogen is

CHEMISTRY · Single correct · CBSE · Chemistry · Structure of Atom · Structure of Atom

Problem

The Bohr radius for the ground state of hydrogen is a0=5.29×10−11 ma_{0}=5.29\times10^{-11}\,\text{m}. Determine the radius of the n=2n=2 orbit in singly-ionized helium (He+\text{He}^{+}). (a) 2.1×10−10 m2.1\times10^{-10}\,\text{m} (b) 1.1×10−10 m1.1\times10^{-10}\,\text{m} (c) 5.3×10−11 m5.3\times10^{-11}\,\text{m} (d) 2.6×10−11 m2.6\times10^{-11}\,\text{m}

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