If lines and and third line passing through form a triangle of area units

MATHEMATICS · Single correct · CBSE · Mathematics · Three-Dimensional Geometry · Three-Dimensional Geometry

Problem

If lines x=y=zx = y = z and x=y2=z3x = \frac{y}{2} = \frac{z}{3} and third line passing through (1,1,1)(1, 1, 1) form a triangle of area 6\sqrt{6} units, then point of intersection of third line with second line will be (1) (1,2,3)(1, 2, 3) (2) (2,4,6)(2, 4, 6) (3) (43,83,123)\left(\frac{4}{3}, \frac{8}{3}, \frac{12}{3}\right) (4) None of these

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