Region T is bounded above by the line

MATHEMATICS · Multi-part · AP · Calculus AB · Applications of Integration · Applications of Integration

Problem

Region T is bounded above by the line y=3−x2y = 3 - \frac{x}{2}, below by the curve y=ln⁡(x+2)y = \ln(x + 2), and above by the x-axis. The two bounding curves intersect exactly once for x>−2x > -2. The region T is revolved about the x-axis to produce a solid. (a) Find, to three decimal places, the x-coordinates where y=3−x2y = 3 - \frac{x}{2} intersects y=ln⁡(x+2)y = \ln(x + 2). (b) Using the values from part (a), specify the x-intervals on which each curve serves as the upper boundary of T. (c) Derive the definite integral(s) that together compute the volume of the solid generated by revolving T about the x-axis. (d) Evaluate the integral expression(s) numerically to three decimal places. (e) Compute the individual volumes contributed by each sub-region identified in part (b) and determine which sub-region accounts for the greatest portion of the total volume, justifying your conclusion with numerical evidence.

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