The improper integral depends on the real parameter

MATHEMATICS · Single correct · AP · Calculus BC · Infinite Sequences and Series · Infinite Sequences and Series

Problem

The improper integral ∫1∞1xp+1 dx\displaystyle \int_{1}^{\infty} \frac{1}{x^{p}+1}\,dx depends on the real parameter pp. For which values of pp does the integral converge? (a) p≥1p\ge 1 (b) 0<p<10<p<1 (c) p>1p>1 (d) All real pp

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