The – graph for a series LCR circuit shows a peak current of at

PHYSICS · Single correct · CBSE · Physics · Alternating Current · Alternating Current

Problem

The

I

–

\omega

graph for a series LCR circuit shows a peak current of

0.50\,\text{A}

\omega = 2.0\times10^{3}\,\text{rad s}^{-1}

. If the applied voltage amplitude is

10\,\text{V}

, the resistance

R

of the circuit is approximately (a)

40\,\Omega

(b)

20\,\Omega

(c)

10\,\Omega

(d)

30\,\Omega