The height of a ball launched vertically is given by h(t)=-16t^ 2 +64t+5 for

MATHEMATICS · Subjective · CBSE · Mathematics · Applications of Derivatives · Applications of Derivatives

Problem

The height of a ball launched vertically is given by

h(t)=-16t^{2}+64t+5

for

t\ge 0

, where

h

is in feet and

t

is in seconds. Determine the time at which the ball reaches its maximum height, and state that maximum height.