When evaluating

MATHEMATICS · Single correct · AP · Calculus AB · Contextual Applications of Differentiation · Contextual Applications of Differentiation

Problem

When evaluating lim⁡x→0cos⁡x−1x2\displaystyle\lim_{x\to 0}\dfrac{\cos x-1}{x^{2}}, a student differentiates numerator and denominator once to obtain −sin⁡x2x\displaystyle\dfrac{-\sin x}{2x} and decides to differentiate again. Which of the following best justifies the need for the additional differentiation? (a) −sin⁡x-\sin x tends to −1-1 while 2x2x tends to 00, so the quotient becomes unbounded; differentiating again may yield a finite limit. (b) Because the denominator contains x2x^{2}, L’Hospital’s Rule must be applied twice—once for each power of xx. (c) The new quotient is still indeterminate because both −sin⁡x-\sin x and 2x2x approach 00 as x→0x\to 0. (d) A second differentiation guarantees the denominator’s order decreases faster than that of the numerator, ensuring convergence.

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