A proton ( , ) is released from rest in a uniform downward electric field of magnitude

PHYSICS · Subjective · AP · Physics 2: Algebra-based · Electric Force Field and Potential · Electric Force Field and Potential

Problem

A proton (mp=1.67×10−27 kgm_{p}=1.67\times10^{-27}\,\text{kg}, qp=+1.6×10−19 Cq_{p}=+1.6\times10^{-19}\,\text{C}) is released from rest in a uniform downward electric field of magnitude 2.0×105 V/m2.0\times10^{5}\,\text{V/m}. (i) Calculate the magnitude and direction of the acceleration of the proton due to the electric field. (ii) Using kinematics, find the speed of the proton after it has moved 2.0 cm2.0\,\text{cm} downward. (iii) Determine the time taken by the proton to travel this distance. (iv) Compare the electric acceleration obtained in part (i) with the acceleration due to gravity and comment on the relative importance of gravitational force in this motion. Present each part in sequence, showing complete derivations and numerical substitution.

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