A manufacturer’s cost (in thousands of rupees) for producing units of an item is…

MATHEMATICS · Single correct · A Level · Mathematics · Differentiation · Differentiation

Problem

A manufacturer’s cost (in thousands of rupees) for producing xx units of an item is given by C(x)=x3−6x2+9x+2,1≤x≤4.C(x)=x^{3}-6x^{2}+9x+2, \quad 1\le x\le 4. The number of units that minimises the cost on this interval is (a) 22 (b) 33 (c) 11 (d) 44

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