The locus of the foot of perpendicular drawn from the centre of the ellipse on any…

MATHEMATICS · Single correct · CBSE · Mathematics · Conic Sections · Conic Sections

Problem

The locus of the foot of perpendicular drawn from the centre of the ellipse x2+3y2=6x^2 + 3y^2 = 6 on any tangent to it is (1) (x2+y2)2=6x2+2y2(x^2 + y^2)^2 = 6x^2 + 2y^2 (2) (x2+y2)2=6x2−2y2(x^2 + y^2)^2 = 6x^2 - 2y^2 (3) (x2−y2)2=6x2+2y2(x^2 - y^2)^2 = 6x^2 + 2y^2 (4) (x2−y2)2=6x2−2y2(x^2 - y^2)^2 = 6x^2 - 2y^2

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