Sulfur dioxide and oxygen react to form sulfur trioxide according to 2 SO₂(g) + O₂(g)…

CHEMISTRY · Multi-part · A Level · Chemistry · Gaseous equilibria (Kp) · Gaseous equilibria (Kp)

Problem

Sulfur dioxide and oxygen react to form sulfur trioxide according to 2 SO₂(g) + O₂(g) ⇌ 2 SO₃(g) For this reaction at a particular temperature, Kp=1.5×104K_p = 1.5 \times 10^{4}. A sealed container at the same temperature is found to have the following partial pressures: PSO2=0.20 atmP_{\text{SO}_2} = 0.20\,\text{atm} PO2=0.10 atmP_{\text{O}_2} = 0.10\,\text{atm} PSO3=0.05 atmP_{\text{SO}_3} = 0.05\,\text{atm} A second researcher elects to write the chemical equation with all stoichiometric coefficients divided by 2. (a) Using the partial pressures given, calculate QpQ_p for the reaction as originally written. Show your calculation explicitly. (b) Compare the QpQ_p obtained in part (a) with KpK_p and predict the direction in which the reaction mixture will spontaneously shift. Explain your reasoning. (c) Calculate the value of the reaction quotient, Qp,scaledQ_{p,\text{scaled}}, that corresponds to the alternative chemical equation written with all coefficients divided by 2. Use the same measured partial pressures. (d) State the numerical relationship between Qp,scaledQ_{p,\text{scaled}} and the QpQ_p from part (a). Explain how this relationship is consistent with the way the equilibrium constant must be transformed for the scaled equation.

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