A conductor of arbitrary shape carries current from to

PHYSICS · Single correct · CBSE · Physics · Moving Charges and Magnetism · Moving Charges and Magnetism

Problem

A conductor ABAB of arbitrary shape carries current II from BB to AA. The length vector AB\mathbf{AB} is oriented from AA to BB. The force F\mathbf{F} experienced by this conductor in a uniform magnetic field B\mathbf{B} is (a) F=−I(AB×B)\mathbf{F}=-I(\mathbf{AB}\times\mathbf{B}) (b) F=I(B×AB)\mathbf{F}=I(\mathbf{B}\times\mathbf{AB}) (c) F=I(BA×B)\mathbf{F}=I(\mathbf{BA}\times\mathbf{B}) (d) All of these

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