For , a quantity satisfies . At , the conditions change and for the quantity follows…

MATHEMATICS · Subjective · AP · Calculus AB · Differential Equations · Differential Equations

Problem

For 0≤t≤4 min0\le t\le 4\,\text{min}, a quantity QQ satisfies dQdt=0.15Q\frac{dQ}{dt}=0.15Q. At t=4 mint=4\,\text{min}, the conditions change and for t>4 mint>4\,\text{min} the quantity follows dQdt=−0.05Q\frac{dQ}{dt}=-0.05Q. Determine the factor Q(7)Q(0)\dfrac{Q(7)}{Q(0)}.

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