For the parametric equations and

MATHEMATICS · Single correct · CBSE · Mathematics · Continuity and Differentiability · Continuity and Differentiability

Problem

For the parametric equations x=t2+1x=t^{2}+1 and y=t3−3ty=t^{3}-3t, the value of dydx\dfrac{dy}{dx} at t=1t=1 is (a) 11 (b) 32\dfrac{3}{2} (c) 00 (d) 33

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