A car travels along a straight road according to the following schedule:
• 0≤t<2s:x=3tm
• 2≤t<6s:x=6m (it halts)
• 6≤t≤10s:x=6−1.5(t−6)m.
(i) Plot a detailed position–time graph for 0–10s on squared paper, choosing a convenient scale.
(ii) Using only the coordinates of the endpoints of each time interval, calculate the average velocity in (a) 0–2s, (b) 2–6s, (c) 6–10s.
(iii) Find the average velocity for the whole motion from t=0 to t=10s and interpret its sign.
(iv) Which interval shows the greatest magnitude of average velocity? Give a reason based on your calculations and the graph.