The value of acceleration due to gravity is at a height ( = radius of the earth) from…

PHYSICS · Single correct · CBSE · Physics · Gravitation · Gravitation

Problem

The value of acceleration due to gravity is g1g_1 at a height h=R2h = \frac{R}{2} ( RR = radius of the earth) from the surface of the earth. It is again equal to g1g_1 and a depth dd below the surface of the earth. The ratio (dR)\left( \frac{d}{R} \right) equals : (1) 49\frac{4}{9} (2) 59\frac{5}{9} (3) 13\frac{1}{3} (4) 79\frac{7}{9}

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