And then is:

CHEMISTRY · Single correct · AP · Chemistry · Thermodynamics and Electrochemistry · Thermodynamics and Electrochemistry

Problem

\Delta G = \Delta H - T\Delta S

and

\Delta G = \Delta H + T\left[\frac{d(\Delta G)}{dT}\right]_P

then

\left(\frac{dE_{\text{cell}}}{dT}\right)_P

is: (a)

\frac{\Delta S}{nF}

(b)

\frac{nE}{\Delta S}

(c)

-nFE_{\text{cell}}

(d)

+nFE_{\text{cell}}